Well, that's a funny first post, but I'll see what I can do.

(a)

Draw a free body diagram. Gravity exerts a force down at the centre of mass of the rod, which is in the middle because the rod is uniform.

The pivot point exerts a force up, and the thread exerts a force up.

(b)

tau = I * alpha

tau is torque in Nm

I is the rod's moment of inertia in kg*m

alpha is angular acceleration in rad/sec*sec (sec squared)

You're given I in the question. You're looking for alpha. Torque is also given by: tau = rFsin(theta) Since the angle is 90 degrees sin(theta) is 1 and can be ignored.

So you're left with tau = rF. r is the distance from the pivot that force F is applied.

so you have

(l/2)*mg = I * alpha.

(c)

Not too sure about this one. Translational acceleration means in a straight line, like drag racers.

If I were desperate I'd just use F = ma but that seems too easy.

(d)

I think it's like (a) except the force from the string is no longer there.

(e)

Hardest part.

Go find your physics textbook and look up "Rotational Motion" It should have something like omega = omega(zero)*t + 0.5*alpha(zero)*t^2.

I believe that's where they key lies.

So, what mods on your car do you have? Surely you didn't join a BMW forum to ask a physics problem.

Dave

1987 BMW 325i

1A Offstream Mechanical Engineering / University of Waterloo